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Constructors and Inheritance | Loop and Break

Constructors and Inheritance

In a hierarchy, it is possible for both base classes and derived classes to have their own constructors. This raises an important question: What constructor is responsible for building an object of the derived class? The one in the base class, the one in the derived class, or both? Here is the answer: The constructor for the base class constructs the base class portion of the object, and the constructor for the derived class constructs the derived class part. This makes sense because the base class has no knowledge of or access to any element in a derived class. Thus, their construction must be separate.
 
When only the derived class defines a constructor, the process is straightforward:
Simply construct the derived class object. The base class portion of the object is constructed automatically using its default constructor. For example, here is a reworked version of Triangle that defines a constructor. It also makes Style private since it is now set by the constructor.

Example

using System;

namespace ConsoleApplication1
{
    using System;
    // A class for two-dimensional objects.
    class TwoDShape
    {
        double pri_width;
        double pri_height;
        // Properties for Width and Height.
        public double Width
        {
            get { return pri_width; }
            set { pri_width = value < 0 ? -value : value; }
        }
        public double Height
        {
            get { return pri_height; }
            set { pri_height = value < 0 ? -value : value; }
        }
        public void ShowDim()
        {
            Console.WriteLine("Width and height are " +
            Width + " and " + Height);
        }
    }
    // A derived class of TwoDShape for triangles.
    class Triangle : TwoDShape
    {
        string Style;
        // Constructor.
        public Triangle(string s, double w, double h)
        {
            Width = w; // init the base class
            Height = h; // init the base class
            Style = s; // init the derived class
        }
        // Return area of triangle.
        public double Area()
        {
            return Width * Height / 2;
        }
        // Display a triangle's style.
        public void ShowStyle()
        {
            Console.WriteLine("Triangle is " + Style);
        }
    }

    class Shapes3
    {
        static void Main()
        {
            Triangle t1 = new Triangle("isosceles", 4.0, 4.0);
            Triangle t2 = new Triangle("right", 8.0, 12.0);
            Console.WriteLine("Info for t1: ");
            t1.ShowStyle();
            t1.ShowDim();
            Console.WriteLine("Area is " + t1.Area());
            Console.WriteLine();
            Console.WriteLine("Info for t2: ");
            t2.ShowStyle();
            t2.ShowDim();
            Console.WriteLine("Area is " + t2.Area());
        }
    }
}

Here, Triangle’s constructor initializes the members of TwoDShape that it inherits along with its own Style field. When both the base class and the derived class define constructors, the process is a bit more complicated because both the base class and derived class constructors must be executed. In this case, you must use another of C#’s keywords, base, which has two uses. The first use is to call a base class constructor. The second is to access a member of the base class that has been hidden by a member of a derived class.

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